(y+1)(y^2-y+1)=x

Solution for (y+1)(y^2-y+1)=x equation:

Simplifying
(y + 1)(y2 + -1y + 1) = x

Reorder the terms:
(1 + y)(y2 + -1y + 1) = x

Reorder the terms:
(1 + y)(1 + -1y + y2) = x

Multiply (1 + y) * (1 + -1y + y2)
(1(1 + -1y + y2) + y(1 + -1y + y2)) = x
((1 * 1 + -1y * 1 + y2 * 1) + y(1 + -1y + y2)) = x
((1 + -1y + 1y2) + y(1 + -1y + y2)) = x
(1 + -1y + 1y2 + (1 * y + -1y * y + y2 * y)) = x
(1 + -1y + 1y2 + (1y + -1y2 + y3)) = x

Reorder the terms:
(1 + -1y + 1y + 1y2 + -1y2 + y3) = x

Combine like terms: -1y + 1y = 0
(1 + 0 + 1y2 + -1y2 + y3) = x
(1 + 1y2 + -1y2 + y3) = x

Combine like terms: 1y2 + -1y2 = 0
(1 + 0 + y3) = x
(1 + y3) = x

Solving
1 + y3 = x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + y3 = -1 + x

Combine like terms: 1 + -1 = 0
0 + y3 = -1 + x
y3 = -1 + x

Simplifying
y3 = -1 + x

Reorder the terms:
1 + -1x + y3 = -1 + x + 1 + -1x

Reorder the terms:
1 + -1x + y3 = -1 + 1 + x + -1x

Combine like terms: -1 + 1 = 0
1 + -1x + y3 = 0 + x + -1x
1 + -1x + y3 = x + -1x

Combine like terms: x + -1x = 0
1 + -1x + y3 = 0

The solution to this equation could not be determined.